Sistem Pendukung Kepututsan Menggunakan Metode SAW (Simple Additive Weighting)
No
|
Nama
|
C1
|
C2
|
C3
|
C4
|
1
|
Joko
|
3
|
3
|
3
|
2
|
2
|
Widodo
|
3
|
3
|
2
|
2
|
3
|
Simamora
|
4
|
4
|
1
|
1
|
4
|
Susilawati
|
1
|
4
|
2
|
1
|
5
|
Dian
|
2
|
3
|
4
|
2
|
6
|
Roma
|
2
|
2
|
4
|
2
|
7
|
Hendro
|
3
|
2
|
3
|
2
|
W=[3,4,5,4]
Matrik
3 3 3 2
3 3 2 2
4 4 1 1
X= 1 4 2 1
2 3 4 2
2 2 4 2
3 2 3 2
Identik dengan
r11 r12 r13 r14
r21 r22 r23 r24
r31 r32 r33 r34
X= r41 r42 r43 r44
r51 r52 r53 r54
r61 r62 r63 r64
r71 r72 r73 r74
Untuk C1
r11
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r21
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r31
= 4 = 4
= 1
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r41
= 1 = 1
= 0.25
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r51
= 2 = 2
= 0.5
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r61
= 2 = 2
= 0.5
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
r71
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 1; 2; 2; 3 ] 4
Untuk C2
r12
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 4; 3; 2; 2 ] 4
r22
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
r32
= 4 = 4
= 1
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
r42
= 4 = 4
= 1
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
r52
= 3 = 3
= 0.75
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
r62
= 2 = 2
= 0.5
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
r72
= 2 = 2
= 0.5
Max [ 3 ; 3; 4; 4; 3; 2; 2 ]
4
Untuk C3
r13
= 3 = 3
= 3
Min [ 3 ; 2; 1; 2; 4; 4; 3] 1
r23
= 2 = 2
= 2
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
r33
= 1 = 1
= 1
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
r43
= 2 = 2
= 2
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
r53
= 4 = 4
= 4
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
r63
= 4 = 4
= 4
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
r73 = 3 = 3 = 3
Min [ 3 ; 2; 1; 2; 4; 4; 3]
1
Untuk C4
r14
= 2 = 2 =
1
Max [ 2 ; 2; 1; 1; 2; 2; 2 ] 2
r24
= 2 = 2
= 1
Max [ 2 ; 2; 1; 1; 2; 2; 2 ] 2
r34
= 1 = 1
= 0.5
Max [ 2 ; 2; 1; 1; 2; 2; 2 ]
2
r44
= 1 = 1
= 0.5
Max [ 2 ; 2; 1; 1; 2; 2; 2 ]
2
r54
= 2 = 2
= 1
Max [ 2 ; 2; 1; 1; 2; 2; 2 ]
2
r64
= 2 = 2
= 1
Max [ 2 ; 2; 1; 1; 2; 2; 2 ]
2
r74
= 2 = 2
= 1
Max [ 2 ; 2; 1; 1; 2; 2; 2 ]
2
Sehingga matrik x yaitu =
0.75 0.75 3 1
0.75 0.75 2 1
1 1 1 0.5
X= 0.25 1 2 0.5
0.5 0.75 4 1
0.5 0.5 4 1
0.75 0.5 3 1
Untuk proses perangkingan menggunakan rumus preferensi
V1 = 3 (0.75) + 4 (0.75) + 5 (3) + 4 (1) = 24.25
V2 = 3 (0.75) + 4 (0.75) + 5 (2) + 4 (1) = 19.25
V3 = 3 (1) + 4 (1) + 5 (1) + 4 (0.5) = 14
V4 = 3 (0.25) + 4 (1) + 5 (2) + 4 (0.5) = 16.75
V5 = 3 (0.5) + 4 (0.75) + 5 (4) + 4 (1) = 28.5
V6 = 3 (0.5) + 4 (0.5) + 5 (4) + 4 (1) = 27.5
V7 = 3 (0.75) + 4 (0.5) + 5 (3) + 4 (1) = 23.25
Sedikit harus Serius :)
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